Objective
Today’s challenge puts your understanding of nested conditional statements to the test. You already have the knowledge to complete this challenge, but check out the Tutorial tab for a video on testing!
Task
Your local library needs your help! Given the expected and actual return dates for a library book, create a program that calculates the fine (if any). The fee structure is as follows:
- If the book is returned on or before the expected return date, no fine will be charged (i.e.: fine = 0).
- If the book is returned after the expected return day but still within the same calendar month and year as the expected return date, fine = 15 Hackos x (the number of days late).
- If the book is returned after the expected return month but still within the same calendar year as the expected return date, the fine = 500 Hackos x (the number of months late).
- If the book is returned after the calendar year in which it was expected, there is a fixed fine of 10000 Hackos.
Input Format
The first line contains 3 space-separated integers denoting the respective day, month, and year on which the book was actually returned.
The second line contains 3 space-separated integers denoting the respective day, month, and year on which the book was expected to be returned (due date).
Constraints
- 1 <= D <= 31
- 1 <= M <= 12
- 1 <= Y <= 3000
- It is guanranteed that the dates will be valid Gregorian calendar dates.
Output Format
Print a single integer denoting the library fine for the book received as input.
Sample Input
1 | 9 6 2015 |
Sample Output
1 | 45 |
Explanation
Given the following return dates:
Actual: Da = 9, Ma = 6, Ya = 2015
Expected: De = 6, Me = 6, Ye = 2015
Because Ye = Ya, we know it is less than a year late.
Because Me = Ma, we know it’s less than a month late.
Because De = Da, we know that it was returned late (but still within the same month and year).
Per the library’s fee structure, we know that our fine will be 15 Hackos X (# days late). We then print the result of 15 X (Da - De) = 15 X (9 - 6) = 45 as our output.
Solution 1
1 | function processData(input) { |
Solution 2
1 | function processData(input) { |