Library Fine

Your local library needs your help! Given the expected and actual return dates for a library book, create a program that calculates the fine (if any). The fee structure is as follows:

1. If the book is returned on or before the expected return date, no fine will be charged (i.e.: fine = 0.
2. If the book is returned after the expected return day but still within the same calendar month and year as the expected return date, fine = 15 Hackos x (the number of days late).
3. If the book is returned after the expected return month but still within the same calendar year as the expected return date, the fine = 500 Hackos x (the number months late).
4. If the book is returned after the calendar year in which it was expected, there is a fixed fine of 10000 Hackos.

Charges are based only on the least precise measure of lateness. For example, whether a book is due January 1, 2017 or December 31, 2017, if it is returned January 1, 2018, that is a year late and the fine would be 10000 Hackos.

Function Description

Complete the libraryFine function in the editor below. It must return an integer representing the fine due.

libraryFine has the following parameter(s):

• d1, m1, y1: returned date day, month and year
• d2, m2, y2: due date day, month and year

Input Format

The first line contains 3 space-separated integers, d1, m1, y1, denoting the respective day, month, and year on which the book was returned.
The second line contains 3 space-separated integers, d2, m2, y2, denoting the respective day, month, and year on which the book was due to be returned.

Constraints

• 
• 
• 
• It is guaranteed that the dates will be valid Gregorian calendar dates.

Output Format

Print a single integer denoting the library fine for the book received as input.

Sample Input

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9 6 2015
6 6 2015

Sample Output

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45

Explanation

Given the following dates:
Returned: d1 = 9, m1 = 6, y = 2015
Due: d2 = 6, m2 = 6, y = 2015

Because , we know it is less than a year late.
Because , we know it’s less than a month late.
Because , we know that it was returned late (but still within the same month and year).

Per the library’s fee structure, we know that our fine will be 15 Hackos x (# days late). We then print the result of 15 x (d2 - d1) = 15 x (9 - 6) = 45 as our output.

Solution

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function libraryFine(d1, m1, y1, d2, m2, y2) {
  return y1 === y2
    ? (m1 === m2
      ? (d1 <= d2 ? 0 : (d1 - d2) * 15)
      : (m1 > m2 ? (m1 - m2) * 500 : 0))
    : (y1 < y2 ? 0 : 10000);
}