Objective
Today we’re learning about running time! Check out the Tutorial tab for learning materials and an instructional video!
Check out the Tutorial tab for learning materials and an instructional video!
A Node class is provided for you in the editor. A Node object has an integer data field, data, and a Node instance pointer, next, pointing to another node (i.e.: the next node in a list).
A removeDuplicates function is declared in your editor, which takes a pointer to the head node of a linked list as a parameter. Complete removeDuplicates so that it deletes any duplicate nodes from the list and returns the head of the updated list.
Note: The head pointer may be null, indicating that the list is empty. Be sure to reset your next pointer when performing deletions to avoid breaking the list.
Today, we’re going further with Binary Search Trees. Check out the Tutorial tab for learning materials and an instructional video!
A level-order traversal, also known as a breadth-first search, visits each level of a tree’s nodes from left to right, top to bottom. You are given a pointer, root, pointing to the root of a binary search tree. Complete the levelOrder function provided in your editor so that it prints the level-order traversal of the binary search tree.
Hint: You’ll find a queue helpful in completing this challenge.
Today, we’re working with Binary Search Trees (BSTs). Check out the Tutorial tab for learning materials and an instructional video!
The height of a binary search tree is the number of edges between the tree’s root and its furthest leaf. You are given a pointer, root, pointing to the root of a binary search tree. Complete the getHeight function provided in your editor so that it returns the height of the binary search tree.
Welcome to Day 18! Today we’re learning about Stacks and Queues. Check out the Tutorial tab for learning materials and an instructional video!
A palindrome is a word, phrase, number, or other sequence of characters which reads the same backwards and forwards. Can you determine if a given string, s, is a palindrome?
To solve this challenge, we must first take each character in s, enqueue it in a queue, and also push that same character onto a stack. Once that’s done, we must dequeue the first character from the queue and pop the top character off the stack, then compare the two characters to see if they are the same; as long as the characters match, we continue dequeueing, popping, and comparing each character until our containers are empty (a non-match means s isn’t a palindrome).
Write the following declarations and implementations:
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